Intersecting family
Named by 3 essays across 2 fields — each of them below, with the objects they name alongside it.
The largest family that always meets
Change the question from "no two comparable" to "every two share an element" and the answer changes shape. The best antichain is a whole layer; the best intersecting family is a star, and the proof is a circle.
The colours a circle forces
Take every pair from five things and join two pairs when they share nothing. Three colours are enough to colour the result so joined pairs differ, and two are not — but no triangle, no dense cluster and no counting argument explains why. The reason is five points on a circle and a direction that cannot be told apart from its opposite, and the same reason, one sphere at a time, settles Kneser's question for every size.
Several colours on every vertex
Give every pair from six points three colours, so that pairs with nothing in common share no colour. Counting says nine colours might do; ten are needed. Stahl conjectured in 1976 exactly how many colours every such problem needs — a formula that meets Lovász's topological answer at one colour a vertex and the obvious answer at k — and a search over stars and triangles confirms it in every case small enough to run.
Named alongside it
The objects these essays reach for when they reach for this one.
Antipodal pairChromatic numberExhaustive searchGraph colouringBinomial coefficientContinuityCounting argumentCounting two waysCyclic orderErdos ko radoExistence proofExtremal problem