Extremal problem
Named by 4 essays across 2 fields — each of them below, with the objects they name alongside it.
Everybody's share of the chains
There are twenty-four ways to build a four-element set one element at a time. Every subset lies on some of them, and no two incomparable subsets share one — so an antichain is a set of disjoint shares of a single whole.
The largest family that always meets
Change the question from "no two comparable" to "every two share an element" and the answer changes shape. The best antichain is a whole layer; the best intersecting family is a star, and the proof is a circle.
The least area a width can hold
Barbier's theorem says every curve of constant width has the same perimeter, which removes perimeter as a way of telling the family apart. Area is not like that — the circle holds the most and the Reuleaux triangle the least — and the reason the minimiser has corners is a constraint rather than a preference.
The largest polygon of diameter one
Among pentagons whose points are never more than one unit apart, the regular pentagon has the most area, and the same is true for every odd number of sides. For six sides it is false: a lopsided hexagon found in 1975 beats the regular one by four per cent. Symmetry wins half the cases and loses the other half, and the reason is parity.
Named alongside it
The objects these essays reach for when they reach for this one.
Binomial coefficientConstant widthCounting argumentCounting two waysPosetAntichainAreaChainConvexityCyclic orderDiameterErdos ko rado