Concept

Majority rule

The rule that settles a yes-or-no question by giving it to the side with more votes. It is the only rule that treats voters alike, treats the two answers alike and never punishes a candidate for gaining support — May's theorem — and it can still produce a set of verdicts that contradict one another when several questions are decided at once.

Named by 9 essays across 2 fields — each of them below, with the objects they name alongside it.

Five rules, and the one condition each of them gives up. A table with one row per aggregation rule and one column per condition, marking which conditions each rule satisfies when run over every profile of the agenda.

Four ways out, and what each costs

An impossibility theorem lists conditions and says no rule has them all. That leaves exactly as many escapes as there are conditions, each of them a real institution — a dictator, a two-stage procedure, a supermajority, a restricted agenda — and each escape's price can be counted rather than argued about.

applied · Judgement aggregation
The nearest consistent verdict: a 3-way tie at distance 4. A table of the 4 consistent judgement sets on the agenda p, q, and p and q, each with its number of disagreements with each of 3 judges and the total; the smallest total is marked.

The nearest consistent verdict

When a court's majorities contradict each other, one repair is to announce the consistent verdict that disagrees with the judges least. It treats the premises and the conclusion alike, which neither of the two standard procedures does. On the classic case it returns a three-way tie; on five judges, with every question weighted equally, it never returns a single answer on a troubled profile at all — and what breaks the tie is a decision about which question matters more.

applied · Judgement aggregation
Which agendas majority can vote on safely. A table of 7 agendas with the size of their largest minimally inconsistent set and the count of inconsistent majority outcomes over all profiles of three and five judges.

Agendas that cannot contradict themselves

A court voting on two unconnected questions never contradicts itself, and neither does one voting on a chain of thresholds. A court voting on two premises and their conjunction sometimes does. What separates them is the size of the smallest sets of judgements that cannot all be true: pairs are harmless, because two majorities always share a judge, and triples are not. The same count says exactly how large a supermajority has to be to stay consistent on any agenda.

applied · Judgement aggregation
Weighted votes: two functions with a cut, and parity without one. For three functions of three letters, the eight assignments placed on a line by a weighted count, with true assignments filled and the threshold marked where one exists.

A plane through the cube

Some truth functions are weighted votes: give each letter a weight, add the weights of the true letters, and say yes when the total passes a threshold. On the cube of assignments, such a function is a plane cutting the true corners from the false. Majority is one. Exclusive-or is not, and never can be — and of the 65,536 functions of four letters, only 1,882 are. The ones that are are exactly what a single artificial neuron can compute.

logic · Truth functions
Every majority pattern on 5 candidates, and the fewest voters that make it. 12 tournaments on 5 candidates: wins 22222 needs 3; wins 32221 needs 3; wins 32221 needs 3; wins 32221 needs 3; wins 33211 needs 3; wins 33211 needs 3; wins 42211 needs 3; wins 43111 needs 3; wins 33220 needs 3; wins 42220 needs 3; wins 33310 needs 3; wins 43210 needs 1.

How few voters any majority needs

Any pattern of head-to-head majorities whatever — cycles within cycles, a candidate who beats the winner of every other contest and loses to its loser — can be produced by voters who each rank the candidates sensibly. McGarvey's recipe needs n(n − 1) of them for n candidates. The truth is far fewer: every pattern on five candidates takes three voters at most, a counting argument shows the number must eventually grow, and it grows only like n divided by its logarithm.

applied · Voting rules
Dodgson's rule: the fewest swaps that make a Condorcet winner. Profile of 9 ballots with no Condorcet winner; Dodgson scores A 1, B 2, C 3, D 6; Borda scores A 15, B 16, C 14, D 9; Copeland A 1, B 1, C 1, D −3.

The fewest swaps to a winner

When no candidate beats every other head to head, Charles Dodgson proposed in 1876 to elect the one that is closest to doing so — the candidate that the fewest swaps of neighbouring names on the ballots would turn into a winner of every contest. The rule is easy to state and hard to compute: the count needs a search, and deciding the winner is provably among the hardest problems of its kind. A much simpler count, the votes still to be won, usually agrees, more often the larger the electorate.

applied · Voting rules
What survives on each agenda, 3 judges. A table of four agendas with, for each, the size of its largest inconsistent set, the number of independent unanimous rules for 3 judges, how many are consistent on every profile, and how many of those are dictatorships, oligarchies and other rules: two unconnected questions 324 of 324; a chain of two thresholds 129 of 324; two premises and their conjunction 7 of 5,832; a ranking of three options 3 of 5,832.

What the agenda leaves standing

Ask for a rule that settles each question from the votes on that question, follows a unanimous court and never contradicts itself, and search every such rule for three judges. On a ranking of three options, three survive: one dictator per judge. On two premises and their conjunction, seven survive: every rule in which a fixed set of judges must all agree. On a chain of thresholds, a hundred and twenty-nine, majority among them. The difference is not in the rules. It is in which answers force which, and whether that forcing ever runs back.

applied · Judgement aggregation
How often each procedure finds the right verdict, with 3 judges of competence 0.7. both true: liable: premises 61.5%, conclusion 48.5%; first only: not liable: premises 83.1%, conclusion 88.6%; second only: not liable: premises 83.1%, conclusion 88.6%; neither: not liable: premises 95.3%, conclusion 97.7%; average 80.7% against 80.9%.

Which vote finds the truth more often

A court that must decide two premises and their conjunction can vote on the premises or on the conclusion, and the two votes sometimes disagree. Suppose there is a right answer and each judge is more often right than wrong. Then the question has an exact answer: for three judges the conclusion vote is more often right when competence is below √½ and the premise vote above it, and in a large court the premise vote wins at any competence — while the conclusion vote turns out to be a built-in standard of proof.

applied · Judgement aggregation
How good each judge must be, as the premises multiply. k = 1: 0.5000; k = 2: 0.7071; k = 3: 0.7937; k = 4: 0.8409; k = 5: 0.8706; k = 6: 0.8909; k = 7: 0.9057; k = 8: 0.9170; k = 9: 0.9259; k = 10: 0.9330.

Every premise makes the verdict vote stricter

A court that must find several things true before it finds liability can vote on each of them or on the verdict. With two elements, judges right seven times in ten are enough for either. With five, the verdict vote needs judges right eighty-seven times in a hundred, or a larger court makes it worse — while the premise vote still needs only better than even. And when any one ground is enough instead of all, the two procedures swap their failures.

applied · Judgement aggregation

Named alongside it

The objects these essays reach for when they reach for this one.

Exhaustive searchJudgement aggregationImpossibility theoremCondorcet cycleQuota ruleCondorcet jury theoremDictatorshipHypercubePropositionVoting ruleAggregationApproximation

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