Resolution
Named by 8 essays across one field — each of them below, with the objects they name alongside it.
A proof with one rule
Two clauses that disagree about exactly one variable can be combined into a third that forgets it; repeat, and if the clauses cannot all be true the empty clause eventually appears — a complete proof system with a single move.
Two literals make an arrow
A clause of two literals, p ∨ q, says that if p is false then q is true, and if q is false then p is true — two arrows. A set of such clauses is a directed graph on the literals, and it is unsatisfiable exactly when some variable and its negation reach each other. Each of those two paths is a chain of resolution steps, and finding them takes time proportional to the size of the input.
A failed search is a proof
Search for an assignment by branching on variables and backing up whenever a clause turns false. If every branch fails, the tree the search leaves behind is itself a resolution refutation: write at each branch point the resolvent of the clauses below it, and the top of the tree is the empty clause. So every limit on short refutations is a limit on every such search — and the pigeonhole clauses, whose refutations are long, defeat them all.
The conclusion is what survives the erasing
Lewis Carroll's puzzles give three premises about four classes — babies, logical people, the despised, crocodile-managers — and ask what follows. Draw all four, shade what the premises rule out, then erase the classes the conclusion is not about: a region survives as empty only if everything above it was. What is left is the conclusion, and erasing a class turns out to be exactly one step of resolution.
A contradiction that is only a sum
Put a variable on every edge of a graph and ask each vertex for an odd or an even number of true edges, with the demands adding up to odd. Add all the demands and every edge is counted twice, so the left side is zero and the right side is one: the contradiction is a single sum. Resolution cannot add. It has to reach the same conclusion clause by clause, and on a graph where every group of vertices has many edges leaving it, that takes exponentially long.
Two terms made equal, and no more
Resolution with variables needs two literals to clash, and they clash only after something has been substituted for their variables. There are infinitely many substitutions that would do. One of them is the most general — every other is it followed by something more — and an algorithm of four rewriting rules finds it or proves there is none. That single computation turns the search for instances from guessing into arithmetic.
Resolving one letter away at a time
Davis and Putnam's procedure of 1960 decides a set of clauses by removing its letters one at a time, replacing every clause that mentions a letter by all the ways of resolving it away. On a cycle the clauses never multiply; on a grid they swell by a factor of three and a half for each extra row, and on the 4 × 4 grid each extra unit of the order's width doubles the peak exactly. The cost is not the size of the formula but how wide it is.
The order that keeps elimination narrow
Eliminating letters one at a time costs whatever the widest step costs, and the least width any order can achieve is the treewidth of the formula's graph. Finding it exactly is NP-hard, but a search over sets of letters instead of sequences finds it for small graphs, and a greedy rule that adds the fewest new edges finds it on 566 of 600 random graphs and misses by more than one only once. On Tseitin's 6 × 6 grid that rule forms twenty-four times fewer resolvents than sweeping row by row. What it cannot do is prove that its order is the best.
Named alongside it
The objects these essays reach for when they reach for this one.
SatisfiabilityRefutationExhaustive searchComplexityProof systemGraphLiteralLower boundNormal formBoolean functionCompletenessDecision procedure