Longest increasing subsequence
Named by 2 essays across one field — each of them below, with the objects they name alongside it.
The longest climb of a shuffle
Erdős and Szekeres guarantee that any n distinct numbers hold a climb or a fall of √n, and there are orders that allow nothing more. Shuffle a deck at random instead and the longest climb is almost exactly 2√n — with fluctuations of size n to the power one-sixth, distributed exactly as the largest eigenvalue of a large random matrix.
The longest climb in a cube
Among n random points in a square, the longest chain rising to the right has about 2√n points, a fact with a famous proof. Put the points in a cube and ask for a chain rising in all three directions, and its length is about c·n^(1/3) for a constant nobody knows. Béla Bollobás and Peter Winkler proved that the constants for every dimension stay below e and creep up to it. The upper bound is a single count of chains, and simulation shows how far below it the real chains fall.
Named alongside it
The objects these essays reach for when they reach for this one.
Random permutationFirst moment methodFluctuationsLimit shapeMonte CarloPartial orderRandom matrixRobinson schenstedStirling formulaYoung tableau