Eulerian circuit
Named by 2 essays across 2 fields — each of them below, with the objects they name alongside it.
Every word once, around a cycle
A cyclic string of eight bits holds all eight three-bit words, each exactly once — and the reason such a thing exists is that the constraint linking overlapping windows is itself the construction.
Two arrows in and two out
An Eulerian circuit enters every point as often as it leaves, so it hands every edge an arrow with the arrows balanced at each point. Count those balanced orientations instead of the circuits and the question turns into the ice in a freezer: on the square grid, where every point has two arrows in and two out, there are about 1.5396 of them per point — Lieb's (4/3)^(3/2), against Pauling's guess of 1.5. Fix the walls of a square of ice and the count becomes 1, 2, 7, 42, 429, 7436: the alternating-sign matrices.
Named alongside it
The objects these essays reach for when they reach for this one.
Exhaustive searchCountingCyclic wordDe bruijn sequenceDeterminantEncodingGraphGraph colouringHierholzer's algorithmOrientationSpanning treeTransfer matrix