Concept

Busy beaver

The largest number of steps, or of marks left on the tape, achieved by any halting Turing machine with a given number of states started on a blank tape. It is known for up to five states and grows faster than any function a program can compute.

Named by 3 essays across one field — each of them below, with the objects they name alongside it.

Also named here as turing machine — the same set of essays touches all of them, so they are one junction rather than several.

All 20,736 two-state Turing machines, by when they halt. A bar chart of the two-state, two-symbol Turing machines by halting step on a blank tape: 1: 6912, 2: 2304, 3: 384, 4: 128, 5: 16, 6: 40, never: 10952.

No algorithm can read what a program does

Whether a program halts cannot be decided by any algorithm. Henry Rice showed in 1953 that the halting problem is not special: no algorithm can decide any property of what a program does — whether it ever prints a 7, whether it computes the successor function, whether it is a virus — except the two properties that hold of every program or of none. Every one of the 20,736 smallest Turing machines can be checked by hand; the theorem says why that stops.

logic · Diagonalisation
Every three-state machine and what becomes of it. halt: 1379; no halting entry: 12492; exact repeat: 361; shifted repeat: 2254; dies backwards: 36; unexplained: 27.

The machines that need a reason never to stop

Run every three-state machine on a blank tape and the ones that halt announce themselves: the longest stops after 21 steps. The work is in the others. Each needs a reason it will never stop, and four simple kinds of reason settle all but 27 of them — machines that sweep back and forth over a growing tape and defeat every check that looks for a repeat.

logic · Diagonalisation
Four dominoes and a match: the same word along the top and the bottom. Dominoes b/ca, a/ab, ca/a, abc/c; the sequence 2, 1, 3, 2, 4 spells abcaaabc on both rows.

Dominoes that no algorithm can match

Emil Post's puzzle has no machines and no programs in it: a handful of dominoes, each with a string on top and a string underneath, and the question whether some row of them, repeats allowed, spells the same word along both edges. No algorithm can answer it for every set of dominoes, because a set can be built whose only matches are a machine's run written out twice, one step out of phase — and three dominoes with strings of three characters already need thirty-six in a row before the edges agree.

logic · Diagonalisation

Named alongside it

The objects these essays reach for when they reach for this one.

Halting problemTuring machineExhaustive searchReductionUndecidabilityBreadth-first searchComputationComputer-assisted proofDecidability

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