Axiom of choice
Named by 11 essays across 4 fields — each of them below, with the objects they name alongside it.
The choice nobody can write down
Given finitely many pairs, picking one thing from each is a finite list of decisions and needs no justification. Given infinitely many, the list cannot be finished — and whether one exists anyway is an axiom, independent of everything else, whose consequences include a theorem most people refuse to believe.
Reached from below, or not at all
Every limit ordinal anybody meets is the end of an increasing sequence — ω, ω·2, ω^ω, all of them approached one step at a time. The first uncountable ordinal is not, and the reason it is not constrains the size of the continuum.
A set that has no size at all
Slide the unit interval along itself by every rational and the points fall into classes. Choose one point from each and the resulting set has no length — not zero, not positive, none: countably many disjoint copies of it would have total length nought or infinity, and the union needs something in between.
The edge that is as big as the ball
In a lattice the boundary of a large ball is a negligible fraction of it. In a tree it is two thirds of it at every size — and that single ratio, not the group's size, is what decides whether a set can be cut into pieces and reassembled into two copies of itself.
A function that adds and is nowhere a line
Every continuous function with f(x + y) = f(x) + f(y) is a straight line through the origin. Drop continuity and, given the axiom of choice, there are others — functions that add perfectly and whose graphs are scattered densely over the whole plane. A finite piece of the construction can be drawn exactly; the whole of it needs a basis of the real numbers that no one can write down.
Infinitely many guessers, finitely many wrong
An infinite line of people each wears a black or white hat, sees every hat in front and none of their own, and must guess their own colour. With a finite line, each guesser is right half the time whatever they agree in advance. With an infinite line and the axiom of choice, they can agree a strategy under which all but finitely many are right — and nobody can carry it out.
Enough partners in every finite group
Hall's theorem says a matching exists unless some group has too few partners between them. On an infinite graph that is false: one vertex that can be paired with anybody, and every other with exactly one, passes the test on every finite group and has no matching at all. The failure needs a vertex with infinitely many choices. Forbid that, and the theorem comes back, by an argument about trees rather than about matchings.
How many colours the plane needs
Colour every point of the plane so that no two points exactly one unit apart share a colour. Seven colours are enough, by a tiling with hexagons, and four are necessary, by a graph of seven points. For sixty-eight years nothing better was known on either side; then in 2018 a graph of 1,581 points showed four is not enough — and the answer is still somewhere from five to seven.
What counting can prove exists
There are only as many continuous functions as points of a line, only as many Borel sets, only countably many definitions — and more sets of reals than any of those. So counting proves that discontinuous functions, non-Borel sets and undefinable numbers exist without exhibiting one. It cannot prove that a set with no length exists, because the sets that have a length are exactly as numerous as all sets, and that difference turns out to be the difference between what the axioms force and what they merely allow.
The choice inside a countable union
A countable union of countable sets is countable: list each set, then walk the grid of all their members along its diagonals. The proof is two lines and every student meets it early. It also makes infinitely many arbitrary choices at once — one listing for each set — and without the axiom of choice the theorem can fail: there are consistent worlds in which the real numbers are a countable union of countable sets, and worlds in which countably many pairs of socks cannot be counted.
A spanning tree for every graph
Every connected graph has a spanning tree: a set of its edges that joins every point and closes no loop. For a finite graph the proof is a greedy pass over the edges. For an infinite graph the greedy pass has to keep going past the end of every list, and the statement turns out to be exactly as strong as the axiom of choice — Zorn's lemma supplies the tree, and the existence of spanning trees in every graph gives back the whole axiom.
Named alongside it
The objects these essays reach for when they reach for this one.
Non-measurable setCountabilityIndependenceCardinalityChoice functionWell-orderingZorns lemmaCompactnessDense setExhaustive searchInfinityMaximal element