wiring
wiring is one function. Everything below came out of it during this
build, at parameters taken from the essays rather than invented for this page — so a figure
here is the same figure a reader meets in an essay, and if the generator changes, this page
changes with it.
At its defaults
show: "determinant"
show: "moves"
show: "swaps"
show: "table"
show: "puzzle"
What it checks while it draws
Collected by running the family and recording what it asserted, not written here. The count is how many separate times the claim was put to the test while these drawings were made.
- all 24 permutations of 4 places are listed ×2
- adding a detour changes the crossing count by an even number ×1
- every reachable arrangement has the same sign-and-blank-distance parity ×1
- exactly half of the 720 arrangements can be reached ×1
- exactly half the permutations are even ×1
- swapping two places flips the sign of every permutation ×1
- swapping two tiles leaves the puzzle unsolvable ×1
- the board is small enough to exhaust — at most six squares ×1
- the detour is between 1 and 3 extra loops ×1
- the long decomposition is the same permutation ×1
- the matrix is 3×3 with whole entries no larger than 20 ×1
- the number of swaps has the parity of the crossing count ×1
- the permutation sends each of its 4 places somewhere different ×1
- the second decomposition is 1 to 3 swaps longer, in pairs ×1
- the short decomposition really is this permutation ×1
- the signed sum over permutations is the determinant ×1
- the strings cross exactly as often as the pairs are out of order ×1
- the table is between 3 and 8 columns wide ×1
- the table is drawn for 2, 3 or 4 places ×1
- the view is one the family draws ×1
- two decompositions of one permutation have the same parity ×1
Where it is called
Changing this generator changes every figure on this list. That is what makes the list worth publishing rather than keeping in a check script.
A shared root, found without finding it
Two polynomials have a root in common exactly when one determinant built from their coefficients is zero. No root is computed, nothing is approximated, and the same construction turns two equations in two unknowns into one equation in one.
AlgebraThe crossings that will not come out even
Draw a rearrangement as strings from one row of pegs to another and count where they cross. The count depends on how the strings are drawn; whether it is odd or even does not, and that single bit is what makes determinants exist and a sliding puzzle unsolvable.