The partition 5 + 4 + 2 + 1 and its conjugate
ferrers is one function. Everything below came out of it during this
build, at parameters taken from the essays rather than invented for this page — so a figure
here is the same figure a reader meets in an essay, and if the generator changes, this page
changes with it.
With nothing chosen
Partitions of 8: odd parts against distinct parts
The Durfee square of 6 + 5 + 5 + 3 + 2 + 1
Every fifth partition count divides, and the rank that says why
p(n) to 40, against the Hardy–Ramanujan estimate
The partition product's coefficients to q¹²
What it checks while it draws
Collected by running the family and recording what it asserted, not written here. The count is how many separate times the claim was put to the test while these drawings were made.
- Gordon's identity, i = 1, at n = 0 ×93
- first identity at 0 ×41
- second identity at 0 ×41
- as many partitions of 30 have largest part 1 as have 1 parts ×30
- the coefficient at 0 is what the theorem says ×27
- the product's coefficient at 0 is p(0) ×19
- the two products agree at 0 ×19
- p(4) is divisible by 5 ×11
- log p(10) is below π√(2n/3), as it is for every n ×10
- the estimate at 10 is within a factor of two of the count ×10
- the ranks modulo 5 split the 30 partitions of 9 into 5 equal classes ×4
- the number partitioned is a whole number between 50 and 5000 ×3
- the partitions of 8 into odd parts and into distinct parts come out equal ×3
- the number of coefficients shown is a whole number between 6 and 20 ×2
- the number sorted by rank leaves 4 on division by 5 ×2
- the number whose partitions are sorted by rank is a whole number between 4 and 14 ×2
- the range is a whole number between 12 and 60 ×2
- a partition whose parts differ by at least 2 ×1
- and at this size it is under 0.04 everywhere ×1
- and changes the number of parts by exactly one ×1
- and it is the largest one that fits ×1
- and it meets the diagonal at ln 2 / c ×1
- and the estimate is closer at the far end than at the near one ×1
- and the partitions the move cannot touch are exactly what survives ×1
- and the ratio climbs towards that ceiling rather than away ×1
- at least one of the divisible values is in the table ×1
- counting by Durfee square accounts for every partition exactly once ×1
- doing it twice gives back what it started as ×1
- each doubling of n brings the ratio closer to ln 2 / c ×1
- each sample is a partition of n ×1
- every listed partition adds to the number it partitions ×1
- partitions of 10: as many with gaps of two as with parts ≡ ±1 (mod 5) ×1
- Ramanujan's value at e^(−2π): √((5 + √5)/2) − (1 + √5)/2 ×1
- removing the staircase leaves a partition into at most k parts ×1
- the average distance to the curve falls at each size ×1
- the congruence drawn is the one modulo 5 or modulo 7 ×1
- the conjugate is a partition of the same number ×1
- the continued fraction equals q^(1/5) times the ratio of the two products ×1
- the curve is its own reflection in the diagonal ×1
- the depth of the continued fraction is a whole number between 20 and 200 ×1
- the gap to the Gumbel law shrinks as n grows ×1
- the largest number counted is a whole number between 20 and 120 ×1
- the largest number in the table is a whole number between 12 and 40 ×1
- the marked values are whole numbers inside the range drawn ×1
- the move gives another partition of the same number into distinct parts ×1
- the number being partitioned is a whole number between 3 and 12 ×1
- the number is a whole number between 5 and 14 ×1
- the number of samples is a whole number between 1 and 8 ×1
- the number whose distinct partitions are paired off is a whole number between 3 and 14 ×1
- the numbers outside the congruence class are not all divisible either ×1
- the partition view is one the family draws ×1
- the partitions listed are all of them ×1
- the parts are a descending list of whole numbers ×1
- the restricted counts are not the unrestricted one ×1
- the same count against parts ≡ ±1 mod 6 fails somewhere ×1
- the series drawn is the partition product or Euler's identity ×1
- the signed count of distinct-part partitions is the product's coefficient ×1
- the square, the arm and the leg account for every dot ×1
- the staircase 1 + 3 + 5 + … holds k² dots ×1
- there is a Durfee square to draw ×1
- three sizes ×1
- turning the diagram over twice gives it back ×1
Where it is called
Every figure on this list is drawn by the same rule, so a change to the rule changes all of them at once. That is why the list is published.
A diagram turned on its side
Write a partition as rows of dots, then read the columns instead. Every theorem in this essay is that one move, and the move proves things that no formula suggests.
DiscreteA polynomial that counts
Hang a counting sequence on the powers of a variable and the two ways of combining choices — this and that, this or that — become multiplication and addition, so a recursion turns into an equation and the equation can be solved.
NumberEvery fifth one divides
p(4) is 5, p(9) is 30, p(14) is 135, and every partition count at a number leaving four on division by five is divisible by five. Ramanujan read it off a table; the explanation is a way of splitting those partitions into five equal heaps.
NumberEvery partition, hidden in a product
Multiply out one factor for each part size and the coefficient of q to the n is the number of partitions of n. Nothing is being approximated: the product is a bookkeeping device that does the counting by multiplying.
NumberThe shape a random partition takes
There are about twenty-four thousand billion billion billion ways to write 1,000 as a sum of whole numbers. Pick one at random, draw its Ferrers diagram, shrink it by the square root of a thousand, and it is almost exactly the curve e^(−cx) + e^(−cy) = 1 with c = π/√6. So is the next one, and the next. A random partition of a large number has a shape, and the shape is known exactly.
NumberThe size of a number with no formula
There is no closed expression for the number of partitions of n. There is an expression for how large it is — with a square root in the exponent and a π in front — and it is accurate enough that rounding a few terms of its refinement gives the exact count.
NumberThe terms that cancel almost everything
Multiply out the product of 1 − q, 1 − q², 1 − q³ and so on, and nearly every coefficient is zero. What survives is a single plus or minus one at 1, 2, 5, 7, 12, 15 — and the reason is a way of pairing partitions off so that each pair cancels.
NumberTwo counts that agree for no visible reason
Write 10 as a sum of whole numbers that differ from each other by at least two, and there are six ways. Write 10 as a sum of numbers that each leave 1 or 4 on division by 5, and there are six ways. The same happens for 20 (thirty-one each), for 40 (three hundred and seventy-four each), for every number anyone has checked and every number there is. The two lists look nothing alike, and no one has found a simple way to turn one into the other.