Two points, and everything one round of compass and straightedge adds
construct is one function. Everything below came out of it during this
build, at parameters taken from the essays rather than invented for this page — so a figure
here is the same figure a reader meets in an essay, and if the generator changes, this page
changes with it.
With nothing chosen
Hippias's quadratrix, traced by two uniform motions
Cutting a 60° angle into 3 with the quadratrix
Squaring the circle, once the quadratrix is drawn
The foot of the quadratrix, approached and never reached
Regular polygons with up to 24 sides, by three instruments
What it checks while it draws
Collected by running the family and recording what it asserted, not written here. The count is how many separate times the claim was put to the test while these drawings were made.
- the 1-th spoke has length √1 ×16
- the 1-th division of the height gives 1/3 of the angle ×6
- after 1 steps the shortfall is θ/(3·4^1) ×5
- the first 18 binary digits of 1/3 are right ×5
- the angle is between 12 and 174 degrees ×4
- 2cos(2π/11) is a root of it ×3
- √(2 + √2) is a root of its stated polynomial ×2
- √2 is a root of its stated polynomial ×2
- the circle about P1 has a centre and a radius ×2
- the circle of radius 1/3 of OP meets the spiral on the arm at 1/3 of the angle ×2
- the intersection named P1 is the one meant ×2
- the objects of step P1 meet ×2
- (1 + √5)/2 is a root of its stated polynomial ×1
- ∛2 is a root of its stated polynomial ×1
- 2 cos(2π/17) is a root of its stated polynomial ×1
- ⁴√2 is a root of its stated polynomial ×1
- a collapsing compass cannot carry a length from one place to another ×1
- a length between 0.5 and 3 ×1
- a number built from square roots has degree a power of two ×1
- a number the table knows ×1
- a rational is a whole numerator over a non-zero whole denominator ×1
- a right angle can be trisected ×1
- a root found by the theorem really is a root of the cubic ×1
- a square with side √π has the area of the unit circle ×1
- a straight angle can be trisected ×1
- a straight line goes to a straight line ×1
- a third of AB takes seven circles with the compass alone ×1
- a third repeats 01 forever ×1
- a zero angle can be trisected ×1
- AL equals BC, as Euclid's second proposition promises ×1
- all eight conjugates of 2 cos(2π/17) are real ×1
- and a number of degree three is not built from them ×1
- and above it ×1
- and at least one is out of reach of both ×1
- and exactly half way from the other end too ×1
- and falls short by about (π/6)·y² ×1
- and five with the compass alone ×1
- and from the other ×1
- and is not half way along after it ×1
- and it fails when the given point is not the midpoint, so the midpoint is what is used ×1
- and it is a different line from the segment ×1
- and it is one radius beyond B ×1
- and it lies on the segment ×1
- and it sits over the midpoint ×1
- and neither centre stays where it was ×1
- and on the segment ×1
- and that crossing and the marked point are both on the circle ×1
- and the centre to a point inside it ×1
- and the diameter really is twice the radius ×1
- and the map undoes itself ×1
- and their images are not equally spaced ×1
- and they are the numbers 2 cos(2πk/17) ×1
- and with the compass alone ×1
- at every positive height the curve stops short of 2/π ×1
- at least one number the compass reaches and the dividers do not ×1
- at least two polygons separate the two instrument sets ×1
- at the end of one turn that length is the whole circumference of the circle through P ×1
- at two different points ×1
- between 4 and 48 sectors ×1
- between three and eight polygons, each with 3 to 24 sides ×1
- between two and eight steps ×1
- between two and seven equal parts ×1
- both crossings exist ×1
- CB′ equals AB: reflecting in the line XY carries A to C and B to B′ ×1
- copies further out look smaller ×1
- copying a length with a rigid compass costs four operations ×1
- corner A is at 0° ×1
- corner B is at 60° ×1
- corner C is at 120° ×1
- corner D is at 180° ×1
- corner E is at 240° ×1
- corner F is at 300° ×1
- cos(θ/3) is a root of the triple-angle cubic ×1
- Dinostratus: the quarter arc is to the side as the side is to the foot of the quadratrix ×1
- divisors are taken of a positive whole number ×1
- dropping the ruler makes the midpoint dearer ×1
- each circle is carried onto itself ×1
- each crossing lies on the polar x·P = 1 ×1
- each line through the point cuts the circle twice ×1
- each map takes the circle to itself ×1
- each step divides the shortfall by four ×1
- each step lands short of the far end ×1
- each step meets the circle ×1
- each step of the compass round the circle meets it ×1
- Euclid's route to copying a length is dearer than a reflection with the same compass ×1
- every coefficient of the minimal polynomial is a whole number ×1
- every computed conjugate is a root of the polynomial ×1
- every image lands on the second line ×1
- every point of the circle lands on the circle ×1
- every point of the first round is where two drawn objects cross ×1
- everything the classical pair reaches, a conic reaches too ×1
- Gauss's condition says the degree is a power of two ×1
- Gauss's criterion and the degree test agree about every polygon ×1
- Gauss's criterion and the degree test agree about the tripled polygon ×1
- in both coordinates ×1
- in every row the sum stands the same fraction of the window short of the third ×1
- nineteen of the polygons up to sixty can be drawn ×1
- no construction of the far corners of the square on AB with six circles or fewer ×1
- no construction of the point one third of the way from A to B with six circles or fewer ×1
- one radicand has a negative reading and the other has none ×1
- one round puts two points off the line ×1
- one unit square to the spoke makes the next spoke √(k + 1) — the step √(1 + x²) ×1
- points far away are carried to the line between the circles ×1
- six points on the circle ×1
- six steps of the radius come back exactly to the start ×1
- sixty degrees cannot be trisected ×1
- some angle in the table the two instruments cannot cut, and the marked one can ×1
- the angle comes from a polygon that can be drawn ×1
- the angle the placed straightedge makes is a third of the original ×1
- the apex is near the segment ×1
- the apex is the carried length from one end ×1
- the apex sees the diameter at a right angle ×1
- the boost is between 0.1 and 1.5 ×1
- the centre is carried to tanh b along the axis ×1
- the centre is equidistant from the ends of the diameter ×1
- the chords cross inside the circle ×1
- the circle about A has a centre and a radius ×1
- the circle about B has a centre and a radius ×1
- the circle about C has a centre and a radius ×1
- the circle about D has a centre and a radius ×1
- the circle about E has a centre and a radius ×1
- the circle about F has a centre and a radius ×1
- the circle about O has a centre and a radius ×1
- the circle about X has a centre and a radius ×1
- the circle about Y has a centre and a radius ×1
- the circle has a sensible radius ×1
- the compass alone never needs fewer moves than both instruments ×1
- the constructed line is parallel to the diameter ×1
- the construction is one of those scored ×1
- the cross ratio is the same on both lines ×1
- the crossing is equidistant from the two ends of the remaining piece ×1
- the crossing point sits on the turning radius at that instant ×1
- the curve meets the radius at angle θ at height θ/90° ×1
- the degree of the cosine is half of n minus one ×1
- the degree's smoothness and the Pierpont condition agree ×1
- the denominator the cosines are taken over is a whole number between 2 and 16 ×1
- the diameter is tilted between 5 and 175 degrees ×1
- the distance from the centre is the fraction of the turn completed ×1
- the fewest moves for the midpoint with ruler and compass ×1
- the fewest moves for the square's far corners with ruler and compass ×1
- the fixed opening is fixed ×1
- the fourth proportional of 2/π, 1 and 1 is π/2 ×1
- the free point sits inside the segment PM ×1
- the gap between them is one sector of the full circle ×1
- the half-chord at the split is the geometric mean √(ab) ×1
- the hendecagon is beyond the trisector ×1
- the hexagon's other four corners take five moves with ruler and compass ×1
- the image of a crossing is the crossing of the images ×1
- the intersection named B is the one meant ×1
- the intersection named B' is the one meant ×1
- the intersection named C is the one meant ×1
- the intersection named D is the one meant ×1
- the intersection named E is the one meant ×1
- the intersection named F is the one meant ×1
- the intersection named G is the one meant ×1
- the intersection named L is the one meant ×1
- the intersection named M is the one meant ×1
- the intersection named P is the one meant ×1
- the intersection named Q is the one meant ×1
- the intersection named X is the one meant ×1
- the intersection named Y is the one meant ×1
- the inverting circle meets the circle of radius AB ×1
- the largest polygon considered is a whole number between 12 and 40 ×1
- the largest polygon tested is a whole number between 12 and 300 ×1
- the line from the point to each touching point is square to the radius — a tangent ×1
- the line through them crosses the common chord at its midpoint ×1
- the long side is √(1 + x²) ×1
- the marked segment between the line and the circle is the radius ×1
- the marked straightedge cuts every angle in the table ×1
- the marks start equally spaced ×1
- the middle mark is half way along before the projection ×1
- the new height is √3/2 ×1
- the nine-gon is not — 3 is a Fermat prime but 9 repeats it ×1
- the number being factorised is a whole number between 1 and 1000000 ×1
- the number of columns in the grid is a whole number between 6 and 20 ×1
- the number of compass steps is a whole number between 2 and 12 ×1
- the number of construction rounds is a whole number between 1 and 2 ×1
- the number of equally spaced marks is a whole number between 3 and 9 ×1
- the number of marks is odd so one of them is the midpoint ×1
- the number whose square root is constructed is between 0 and 12 ×1
- the objects of step B meet ×1
- the objects of step B' meet ×1
- the objects of step C meet ×1
- the objects of step D meet ×1
- the objects of step E meet ×1
- the objects of step F meet ×1
- the objects of step G meet ×1
- the objects of step L meet ×1
- the objects of step M meet ×1
- the objects of step P meet ×1
- the objects of step Q meet ×1
- the objects of step X meet ×1
- the objects of step Y meet ×1
- the perpendicular at the join has height √n ×1
- the Pierpont condition and the degree's smoothness agree ×1
- the point found is exactly half way along ×1
- the point found is halfway along ×1
- the point is outside the circle ×1
- the polar of an outside point cuts the circle ×1
- the polygon has a prime number of sides, so the degree is (n − 1)/2 ×1
- the polygon is a whole number between 5 and 23 ×1
- the polynomial has no rational root, so it does not factor off a linear piece ×1
- the polynomial has the degree the totient predicts ×1
- the region lies between the inscribed and circumscribed sectors ×1
- the second line is tilted between 0.15 and 0.75 ×1
- the second round is shown or not ×1
- the segment cut off is longer than the radius far out and shorter close in ×1
- the segment is between 0.4 and 6 units long ×1
- the segment is between half a unit and two units long ×1
- the segment really is longer than the opening can span in one go ×1
- the seven-gon is not ×1
- the seventeen-gon is constructible ×1
- the sliding point and the centre are the same distance from the near crossing ×1
- the spiral runs to √4 … √17 ×1
- the tangent cuts off, on the perpendicular through the centre, a length equal to the arc of radius OP through the angle turned ×1
- the tangent is drawn a quarter, half, three quarters or a whole turn out ×1
- the totient of n above two is even ×1
- the triangles to √17 go round less than once, so none overlaps ×1
- the two arcs about D and E meet ×1
- the two arcs of the fixed opening meet ×1
- the two crossings sit at the same height, so the line is parallel ×1
- the two readings multiply to the norm ×1
- the two tangents of each circle at the crossing points meet on the line of centres ×1
- the view is one of root, trisect, polygons, compass, hexagon, straightedge, neusis, reach, parallel, poncelet, rusty, conics, hendecagon, lemoine, lemoinetable, quadratrix, quaddivide, quadsquare, quadfoot, quadreach, cauer, cauerorbit, polar, pair, theodorus, dividers, conjugates, embed, seventeen, mean, spiral, spiraldivide, spiraltangent, spiralarea, bisectlimit, bisecterror, binaryratio, cheapmid, cheaptable, cheapsquare, cheapthird, cheapgrowth, cheaphex ×1
- the walk was built ×1
- three steps of the radius reach the point twice as far away ×1
- three steps reach the far side, which is the doubling ×1
- twenty-four of the polygons up to a hundred can be drawn ×1
- two circles, apart or meeting, not touching ×1
- two points and one round of drawing give four more ×1
- two positive lengths ×1
- two to five boosts up to 2.5 ×1
- what is left is short enough for the fixed opening to span ×1
- whatever compass and straightedge reach, a trisector reaches too ×1
- which is not the centre ×1
- which makes it that piece's midpoint ×1
Where it is called
Every figure on this list is drawn by the same rule, so a change to the rule changes all of them at once. That is why the list is published.
A curve that divides any angle
Let a radius turn at a steady rate while a horizontal line falls at a steady rate, both finishing together, and mark where they cross. The curve they trace turns heights into angles, so dividing a height — which a ruler and compass can always do — divides the angle in the same ratio. The same curve meets its base at 2/π of the side, a length from which a square with the area of a circle follows. It reaches what no marked ruler or conic can, and the ancient objection to it is exact.
ComputationA quintic a sliding mark reaches
The eleven-sided polygon needs a number of degree five, and five is not a product of twos and threes — so no conic and no angle trisector reaches it. A ruler with two scratches does, which places the marked ruler strictly above the conics and leaves its exact reach unknown.
ComputationA third reached only in the limit
No compass-and-straightedge construction trisects every angle. But a quarter, plus a quarter of a quarter, plus a quarter of that, and so on, adds up to a third — and each of those pieces is two bisections away. So an angle can be trisected by bisecting forever, every stage exact and the shortfall shrinking to a quarter each time. The construction never ends, and that is precisely what Wantzel's proof forbids: a construction is a finite thing, and a third of a general angle is only reached in the limit.
AlgebraA tower whose degrees multiply
Treat a field containing another as a vector space over it, and the size of an extension becomes a dimension — one that multiplies along a tower, so that three impossible constructions become arithmetic about which numbers divide which.
ComputationEvery step is a square root
A line meets a line by solving a linear equation and a circle by solving a quadratic one. There is no third case, so the numbers a construction reaches can only ever double in complexity — and a doubling is a thing that can be counted.
ComputationOne circle, and a straightedge
A straightedge alone cannot bisect a segment, so it cannot draw a parallel, so it can construct almost nothing. Draw one circle anywhere and mark its centre and everything a compass could ever have done becomes available — the circle is never needed again.
ComputationThe angle that will not divide by three
Halving an angle costs one circle. Cutting it in three means solving a cubic, and for sixty degrees that cubic has no rational root — but plenty of angles do trisect, and which ones is a question with a countable answer.
ComputationThe centre a straightedge cannot find
Give a straightedge one circle and its centre, and it can do everything a compass can. Take the centre away and it cannot even find it again — because to a straightedge a circle has no centre. The maps that keep a circle and its straight lines are the motions of the hyperbolic plane, and in that plane the centre is a point like any other.
ComputationThe circle that will not square
The other three impossibilities are a number having the wrong degree. This one is a number having no degree at all — and that is a claim no finite search can establish, which makes it the one place in this field where the picture has to admit what it is not doing.
ComputationThe compass that will not open
Fix the compass at one opening and never change it. That looks like a serious loss — a circle of a given radius through a given point is the compass's whole job — and it turns out to cost nothing at all, for reasons that are arithmetic rather than geometric.
ComputationThe cube that will not double
Doubling a cube needs an edge in the ratio of the cube root of two. That number satisfies an equation of degree three, three does not divide any power of two, and the oldest open problem in geometry closes in a line.
ComputationThe fewest moves to draw it
Every construction with ruler and compass is a sequence of moves — draw this line, draw that circle — and it is natural to ask for the shortest. Nobody can answer that by cleverness alone, but a machine can answer it by trying everything: the midpoint of a segment takes four moves and no fewer, the square on it five, a third of it five. Take the ruler away and the compass pays for it: six circles for the midpoint, seven for the square.
ComputationThe lengths dividers cannot reach
A pair of dividers carries a length from one place to another and draws nothing. With a straightedge it finds midpoints, parallels and right angles, and it draws the regular 17-gon. It cannot draw a segment of length √(1 + √2) — and the reason is not on the page at all, but in the other root of the equation that number solves.
ComputationThe mark that changes what is reachable
Two thousand years of failure to trisect an angle with compass and straightedge was failure at a stated set of operations. Scratch two marks on the straightedge and Archimedes trisects any angle in four steps — because the new operation solves a cubic, and the old ones could only ever solve quadratics.
AlgebraThe polygon an equation forces
The n solutions of z to the n equals one are the corners of a regular polygon, and nearly everything about them — that they form a group, that they sum to zero, that the equation factors into pieces with whole-number coefficients — is that picture read carefully.
ComputationThe price of a construction
Three theorems have shown that a compass alone, a straightedge with one circle, and a compass stuck at one opening all reach exactly the points a full set of instruments reaches. None of them said what the journey costs. Émile Lemoine priced every movement of the hand in 1888, and by his count a compass that collapses when lifted — Euclid's — pays twenty-one operations, by Euclid's own method, for what a compass that holds its opening does in four.
ComputationThe spiral that measures its own circle
Let a ray turn steadily while a point moves steadily out along it, and the point draws Archimedes' spiral. Distance from the centre is then proportional to angle, so dividing a length divides an angle in any ratio. The spiral's second power is stranger: the tangent at the end of the first turn cuts off, on a line through the centre, a straight length exactly equal to the circumference of the circle through that end — a curved length laid out straight, and with it the circle squared. The catch is the tangent itself.
ComputationThe straightedge buys nothing
Every point a compass and a straightedge can construct together can be constructed by the compass alone. The straightedge draws lines nobody needs; the compass does the work, and the proof that it does is an inversion performed with arcs.
GeometryThree trisectors and a triangle nobody expected
Cut every angle of a triangle into three. The trisectors nearest each side meet in three points, and those three points are always the corners of an equilateral triangle — for every triangle there is, with no exceptions and no reason anybody finds obvious.
ComputationTwo instruments with one reach
Allow every conic to be drawn at will, or allow an angle to be cut in three. The two permissions look nothing alike and reach exactly the same numbers — because what an operation buys is a degree, and both of these buy three.
ComputationWhat two points can build
A compass and a straightedge are not a craft. They are two operations on a set of points, applied over and over, and writing them that way turns "can this be drawn?" into a question with an answer.
ComputationWhich polygons can be drawn
Three sides yes, seven no, seventeen yes. The list of constructible regular polygons is neither everything nor almost nothing, and the pattern in it is a fact about which numbers are one less than a power of two.