A rule for moving between 3 states
chain is one function. Everything below came out of it during this
build, at parameters taken from the essays rather than invented for this page — so a figure
here is the same figure a reader meets in an essay, and if the generator changes, this page
changes with it.
With nothing chosen
Waiting for each pattern, as the coin tilts
Conway's odds on a coin that shows heads 60 times in a hundred
Who wins each matchup, as the coin tilts
The second player's best reply, as the coin tilts
How much the first player can guarantee, as the coin's bias moves
What it checks while it draws
Collected by running the family and recording what it asserted, not written here. The count is how many separate times the claim was put to the test while these drawings were made.
- the wait for a new one at 0 seen is 6/6 ×21
- after 5 shuffles the distance is Bayer and Diaconis's 0.924 ×6
- the 6 waits add to 6 times the harmonic sum ×3
- a deck of 4 to 520 cards ×1
- a pattern losing both two-way races need not come last three-way ×1
- a run of the game reproduces the expected length ×1
- a three-toss pattern that beats both others two-way also wins the three-way race ×1
- a triple with no circle and no pattern beating both others holds a tie ×1
- a walk of 40000 steps spends about the solved share of its time at A ×1
- a walk of 40000 steps spends about the solved share of its time at B ×1
- a walk of 40000 steps spends about the solved share of its time at C ×1
- and agree better than the two smallest do ×1
- and at most twice the conductance ×1
- and comes back to A about as often as the solve says ×1
- and comes back to B about as often as the solve says ×1
- and comes back to C about as often as the solve says ×1
- and equal chances are the best case — any unevenness makes the wait longer ×1
- and it is still climbing at the same rate ×1
- and it really is stationary ×1
- and its narrowest door is half the ring, conductance 1/m ×1
- and no better than the true minimum ×1
- and on the expected length of the race ×1
- and so does a four-toss one ×1
- and so does the riffle shuffle's ×1
- and that sum is bounded, so the shares can be normalised ×1
- and the chance of ending at the top satisfies B = R + Q B ×1
- and the chance of ever coming back is less than one ×1
- and the chance of winning is the share of the stake held ×1
- and the share of wins reproduces the computed chance ×1
- and the traffic round the cycle is not equal in the two directions ×1
- and they are the shares the rule leaves alone ×1
- and they do not all take the same time, although every one of them has the same chance in any given window ×1
- as much traffic goes from A to B as comes back ×1
- as much traffic goes from A to C as comes back ×1
- as much traffic goes from A to D as comes back ×1
- as much traffic goes from A to E as comes back ×1
- as much traffic goes from B to C as comes back ×1
- as much traffic goes from B to D as comes back ×1
- as much traffic goes from B to E as comes back ×1
- as much traffic goes from C to D as comes back ×1
- as much traffic goes from C to E as comes back ×1
- as much traffic goes from D to E as comes back ×1
- at even odds the expected length is k times N minus k ×1
- at least two chains, so the comparison says something ×1
- away from even odds the chance of winning is the ratio the odds give ×1
- between six and sixty steps are drawn ×1
- between two and four step-up chances are drawn ×1
- between two and six patterns of two to five coin tosses ×1
- cube dimensions between 4 and 2048 ×1
- each larger cube falls over a smaller share of its own mixing time ×1
- every chain named is one the family carries ×1
- every point is inside the drawn axes ×1
- every start can go either way ×1
- every state has somewhere to go ×1
- every state holds a share ×1
- every vertex of the graph has a neighbour ×1
- HH: the chain's answer and the overlap sum agree ×1
- HH's wait is between the window size and twice it less two ×1
- HHH against HHT is settled by the toss after the first HH ×1
- HHH: the chain's answer and the overlap sum agree ×1
- HHH's three-way chance is its chance against TTH alone ×1
- HHH's wait is between the window size and twice it less two ×1
- HHHH: the chain's answer and the overlap sum agree ×1
- HHHH's wait is between the window size and twice it less two ×1
- HHT and THH wait alike ×1
- HHT beats HTH with chance 1/(1 + q) ×1
- HHT: the chain's answer and the overlap sum agree ×1
- HHT's wait is between the window size and twice it less two ×1
- HT: the chain's answer and the overlap sum agree ×1
- HT's wait is between the window size and twice it less two ×1
- HTH: the chain's answer and the overlap sum agree ×1
- HTH's wait is between the window size and twice it less two ×1
- HTHT: the chain's answer and the overlap sum agree ×1
- HTHT's wait is between the window size and twice it less two ×1
- HTT and TTH wait alike ×1
- HTT: the chain's answer and the overlap sum agree ×1
- HTT's wait is between the window size and twice it less two ×1
- HTTH: the chain's answer and the overlap sum agree ×1
- HTTH's wait is between the window size and twice it less two ×1
- HTTT: the chain's answer and the overlap sum agree ×1
- HTTT's wait is between the window size and twice it less two ×1
- iterating from A reaches the same share for A ×1
- iterating from A reaches the same share for B ×1
- iterating from A reaches the same share for C ×1
- laziness leaves no eigenvalue below zero ×1
- lumping by weight loses nothing ×1
- no three three-toss patterns beat one another in a circle ×1
- no two edge weights are drawn on top of one another ×1
- no two of the three are tied ×1
- on a fair coin the best reply to HHH is THH ×1
- on a fair coin the best reply to HHT is THH ×1
- on a fair coin the best reply to HTH is HHT ×1
- on a fair coin the best reply to HTT is HHT ×1
- on a fair coin the best reply to THH is TTH ×1
- on a fair coin the best reply to THT is TTH ×1
- on a fair coin the best reply to TTH is HTT ×1
- on a fair coin the best reply to TTT is HTT ×1
- on a fair coin the first player can guarantee a third and no more ×1
- on dumbbells the gap falls as the conductance itself ×1
- on rings the fall takes the same share of the clock at every size ×1
- on rings the gap falls as the square of the conductance ×1
- one of the three always appears first ×1
- one to four matchups ×1
- p³ passes a half at the cube root of a half's reciprocal ×1
- rings run with the lower line and dumbbells with the upper ×1
- row A holds probabilities ×1
- row B holds probabilities ×1
- row C holds probabilities ×1
- row D holds probabilities ×1
- row E holds probabilities ×1
- row F holds probabilities ×1
- row G holds probabilities ×1
- row H holds probabilities ×1
- shuffling again never makes a deck less random ×1
- some four-toss triples do ×1
- TH: the chain's answer and the overlap sum agree ×1
- TH's wait is between the window size and twice it less two ×1
- the alternating sum over subsets and the integral of one minus the product agree ×1
- the best sweep cut is within Cheeger's guarantee √(2·gap) ×1
- the chain and the gamblers agree on HHH ×1
- the chain and the gamblers agree on HHHT ×1
- the chain and the gamblers agree on HTT ×1
- the chain and the gamblers agree on HTTH ×1
- the chain and the gamblers agree on TTH ×1
- the chain and the gamblers agree on TTHH ×1
- the chain is one of mixing, cycle, reducible, lazy ×1
- the chain is one the family carries ×1
- the chain with the smaller gap really does take longer ×1
- the chance of a win is strictly between nothing and everything ×1
- the chances of leaving A add to one ×1
- the chances of leaving B add to one ×1
- the chances of leaving C add to one ×1
- the chances of leaving D add to one ×1
- the chances of leaving E add to one ×1
- the chances of leaving F add to one ×1
- the chances of leaving G add to one ×1
- the chances of leaving H add to one ×1
- the collection is one the family knows ×1
- the corroborating run is between 500 and 40,000 games ×1
- the cube's window shrinks against its mixing time ×1
- the cycle's forward chance is between a half and one ×1
- the cycle's shares are stationary even so ×1
- the cycle's stationary shares are equal ×1
- the distance never exceeds the chance a coordinate is unpicked ×1
- the distance to stationarity never rises ×1
- the drawing runs out to between 10 and 60 states ×1
- the Eulerian numbers count every ordering once ×1
- the expected number of steps satisfies t = 1 + Q t ×1
- the expected return to A is one over its share ×1
- the expected return to B is one over its share ×1
- the expected return to C is one over its share ×1
- the family is rings or dumbbells ×1
- the first player is favoured only when the coin is very biased ×1
- the game is played over between four and nine totals ×1
- the gap is at least half the square of the conductance ×1
- the graph is connected, so one is a simple eigenvalue ×1
- the graph is one of cycle, dumbbell, grid, cube, complete, path, twogrids, lollipop ×1
- the graph is small enough to search every vertex set ×1
- the long-run shares are drawn only for a chain that has them ×1
- the mean count of 1s follows (n/2)(1 − (1 − 1/n)^t) ×1
- the measured decay rate is the second eigenvalue ×1
- the measured mixing time follows the eigenvalue's prediction ×1
- the number of kinds to collect is between 2 and 16 ×1
- the odds formula for HHH against HHT ×1
- the odds formula for HHH against HTH ×1
- the odds formula for HHH against HTT ×1
- the odds formula for HHH against THH ×1
- the odds formula for HHH against THT ×1
- the odds formula for HHH against TTH ×1
- the odds formula for HHH against TTT ×1
- the odds formula for HHT against HHH ×1
- the odds formula for HHT against HTH ×1
- the odds formula for HHT against HTT ×1
- the odds formula for HHT against THH ×1
- the odds formula for HHT against THT ×1
- the odds formula for HHT against TTH ×1
- the odds formula for HHT against TTT ×1
- the odds formula for HTH against HHH ×1
- the odds formula for HTH against HHT ×1
- the odds formula for HTH against HTT ×1
- the odds formula for HTH against THH ×1
- the odds formula for HTH against THT ×1
- the odds formula for HTH against TTH ×1
- the odds formula for HTH against TTT ×1
- the odds formula for HTT against HHH ×1
- the odds formula for HTT against HHT ×1
- the odds formula for HTT against HTH ×1
- the odds formula for HTT against THH ×1
- the odds formula for HTT against THT ×1
- the odds formula for HTT against TTH ×1
- the odds formula for HTT against TTT ×1
- the odds formula for THH against HHH ×1
- the odds formula for THH against HHT ×1
- the odds formula for THH against HTH ×1
- the odds formula for THH against HTT ×1
- the odds formula for THH against THT ×1
- the odds formula for THH against TTH ×1
- the odds formula for THH against TTT ×1
- the odds formula for THT against HHH ×1
- the odds formula for THT against HHT ×1
- the odds formula for THT against HTH ×1
- the odds formula for THT against HTT ×1
- the odds formula for THT against THH ×1
- the odds formula for THT against TTH ×1
- the odds formula for THT against TTT ×1
- the odds formula for TTH against HHH ×1
- the odds formula for TTH against HHT ×1
- the odds formula for TTH against HTH ×1
- the odds formula for TTH against HTT ×1
- the odds formula for TTH against THH ×1
- the odds formula for TTH against THT ×1
- the odds formula for TTH against TTT ×1
- the odds formula for TTT against HHH ×1
- the odds formula for TTT against HHT ×1
- the odds formula for TTT against HTH ×1
- the odds formula for TTT against HTT ×1
- the odds formula for TTT against THH ×1
- the odds formula for TTT against THT ×1
- the odds formula for TTT against TTH ×1
- the overlap sum is the expected wait for HHH ×1
- the overlap sum is the expected wait for HHT ×1
- the overlap sum is the expected wait for HTH ×1
- the overlap sum is the expected wait for HTT ×1
- the overlap sum is the expected wait for THH ×1
- the overlap sum is the expected wait for THT ×1
- the overlap sum is the expected wait for TTH ×1
- the overlap sum is the expected wait for TTT ×1
- the panels drawn are genuinely different cases ×1
- the patterns compared are all the same length ×1
- the points to fit a slope through are not all at one place ×1
- the return chances satisfy the rule that defines them ×1
- the ring's does not ×1
- the ring's gap is (1 − cos 2π/m)/2 ×1
- the rows never move further apart as the power rises ×1
- the run is between 2,000 and 400,000 steps ×1
- the run spends its time in A in the computed share ×1
- the run spends its time in B in the computed share ×1
- the run spends its time in C in the computed share ×1
- the same current flows across every edge of the cycle ×1
- the series is added over between 60 and 4,000 terms ×1
- the share read off the weights is the share the equations give ×1
- the shares add to one ×1
- the shortfall reaches one standard deviation at ½ n ln n ×1
- the solved share for A survives a step ×1
- the solved share for B survives a step ×1
- the solved share for C survives a step ×1
- the stationary distribution adds to one ×1
- the system and the chain agree ×1
- the system is not singular ×1
- the top eigenvalue of a walk is one ×1
- the traffic between neighbours balances ×1
- the two largest cubes' curves agree on this clock ×1
- the view is one the family draws ×1
- the walk is between a thousand and four hundred thousand steps ×1
- the weighted Conway odds give the chain's answer ×1
- the weights add to the geometric sum they are ×1
- the weights are a square table of between three and six states ×1
- the weights are all one, so the sum grows without bound ×1
- the weights are symmetric and never negative ×1
- the weights grow, so there is nothing to normalise ×1
- THH beats HHH unless the first three tosses are heads ×1
- THH beats HHT unless the first two tosses are heads ×1
- three patterns of one length ×1
- TT: the chain's answer and the overlap sum agree ×1
- TT's wait is between the window size and twice it less two ×1
- TTH wins the spoiler race only by opening with TT ×1
- while the wait for the rarest kind alone is already a lower bound ×1
Where it is called
Every figure on this list is drawn by the same rule, so a change to the rule changes all of them at once. That is why the list is published.
A coin that lets the first player win
On a fair coin the second player in Penney's game always has a better pattern than the first, and the first can hold them to no worse than two to one. Bend the coin and every overlap is paid for in the letters it uses: the replies change, the first player's share swings between a third and a half, and past a heads chance of 1/∛2 the first player simply names HHH and wins.
ProbabilityA walk that samples a distribution
When a distribution can be evaluated but not drawn from, a wandering point can be arranged to visit each state as often as its weight says. The rule needs no normalising constant, compares two weights and steps or stays.
ProbabilityAn average that never settles
The average of many independent quantities is supposed to steady as their number grows. For one famous distribution it does not steady at all — the average of a thousand draws has exactly the same distribution as a single draw, and no amount of further averaging changes it.
ComputationEvery word once, around a cycle
A cyclic string of eight bits holds all eight three-bit words, each exactly once — and the reason such a thing exists is that the constraint linking overlapping windows is itself the construction.
ProbabilityHow long until every one turns up
Draw at random from six equally likely kinds until all six have appeared. The wait is not six draws, and it is not sixty; it is fourteen point seven, and the number is a harmonic sum wearing a hat.
ProbabilityHow long until it forgets
The essays before this one settle where a chain ends up and how much time it spends there, and none of them asks how long the settling takes. That question has an exact answer, it is a single number, and it is the only thing any practical use of a chain depends on.
ProbabilityThe chain that runs the same backwards
Put weights on the edges of a graph, step to a neighbour in proportion to them, and the long-run share of a state is its own weight over the total — read straight off the picture, with nothing to solve. The condition that makes that work is strictly stronger than being stationary.
ProbabilityThe chain that stops
Give a chain a state it cannot leave and there is no long run to find — every walk ends. What is worth computing instead is how long it lasts and where it finishes, and both are exact answers to a linear system rather than limits of anything.
ProbabilityThe forgetting that happens all at once
A single small chain forgets its start gradually, a little more with every step. A family of large ones can do something different — stay almost perfectly informed about where it began, and then lose all of it inside a window far shorter than the wait. That cliff is the cutoff phenomenon, and it is why "seven shuffles" is an answer rather than a convention.
ProbabilityThe narrowest door sets the pace
How fast a chain forgets is an eigenvalue, and nobody can compute the eigenvalues of a chain worth studying. Cheeger's inequality trades the eigenvalue for a picture — the narrowest door in the state space — and pins the one between the square of the other and twice it. Both ends of that range are reached, on graphs small enough to search completely.
ProbabilityThe one that hardly ever comes up
Make the kinds unequally likely and the tidy decomposition into stages fails, because a stage's rate now depends on which kinds turned up rather than on how many. What replaces it is an alternating sum over every subset — and the rarest kind turns out to be nearly the whole answer.
ProbabilityThe rule that forgets where it came from
A walk between a few states, with the next step decided by the current one and nothing else. Run it long enough and the starting point stops mattering — but only when two conditions hold, and both of them have a picture in which they fail.
ProbabilityThe time spent and the share held
Stationary shares are a limit of distributions — where the walk probably is after many steps. Here the question is about a single walk: the fraction of its time spent in each state is that state's share, and the expected wait between visits is exactly the reciprocal.
ProbabilityThree patterns in a circle
Race three coin patterns at once and the gamblers' accounting still gives each one's chance of arriving first — one fairness equation per pattern. What it does not give is any way to read the three-way result off the two-way ones. HHHT, TTHH and HTTH beat one another in a circle, and HHH loses both its head-to-head races and still finishes ahead of one of the patterns that beat it.
ProbabilityTwo barriers and a fair game
A fair walk between two absorbing barriers is ruined with a probability that is a straight line in the starting stake, and lasts for a number of steps that is the product of what each side can lose. Both facts come from the same two-line recurrence, and both are bad news for the smaller player.
ProbabilityTwo patterns, one chance, different waits
HTH and HTT are equally likely in any given window of three tosses. Waiting for HTH takes ten tosses on average and waiting for HTT takes eight, and the difference is not about probability at all — it is about what a failed attempt leaves behind.
ProbabilityWhere the shares have nowhere to go
On finitely many states, a chain that can reach everywhere and is not forced into a rhythm settles down. Give it infinitely many and both conditions can hold while the walk leaves and never returns — or returns with certainty and takes an unbounded average time about it.